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201331531245 = 35131032469391
BaseRepresentation
bin1011101110000001001…
…0110101110111101101
3201020200010210110222110
42323200102311313231
511244311332444440
6232253533234233
720355116531205
oct2734022656755
9636603713873
10201331531245
1178425445349
1233029632979
1315ca71470a0
149a5cc8d405
1553852e2080
hex2ee04b5ded

201331531245 has 16 divisors (see below), whose sum is σ = 346909715712. Its totient is φ = 99117061440.

The previous prime is 201331531241. The next prime is 201331531279. The reversal of 201331531245 is 542135133102.

It is not a de Polignac number, because 201331531245 - 22 = 201331531241 is a prime.

It is a super-3 number, since 3×2013315312453 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201331531241) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 516234501 + ... + 516234890.

It is an arithmetic number, because the mean of its divisors is an integer number (21681857232).

Almost surely, 2201331531245 is an apocalyptic number.

It is an amenable number.

201331531245 is a deficient number, since it is larger than the sum of its proper divisors (145578184467).

201331531245 is a wasteful number, since it uses less digits than its factorization.

201331531245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1032469412.

The product of its (nonzero) digits is 10800, while the sum is 30.

Adding to 201331531245 its reverse (542135133102), we get a palindrome (743466664347).

The spelling of 201331531245 in words is "two hundred one billion, three hundred thirty-one million, five hundred thirty-one thousand, two hundred forty-five".

Divisors: 1 3 5 13 15 39 65 195 1032469391 3097408173 5162346955 13422102083 15487040865 40266306249 67110510415 201331531245