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2013322110307 = 17118430712371
BaseRepresentation
bin11101010011000011010…
…110010110010101100011
321010110201212202011200221
4131103003112112111203
5230441240430012212
64140524000023511
7265312666400554
oct35230326262543
97113655664627
102013322110307
11706932931502
12286241601b97
13117b175a5991
146d633d0632b
1537587859807
hex1d4c3596563

2013322110307 has 4 divisors (see below), whose sum is σ = 2131752822696. Its totient is φ = 1894891397920.

The previous prime is 2013322110269. The next prime is 2013322110383. The reversal of 2013322110307 is 7030112233102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013322110307 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013322116307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59215356169 + ... + 59215356202.

It is an arithmetic number, because the mean of its divisors is an integer number (532938205674).

Almost surely, 22013322110307 is an apocalyptic number.

2013322110307 is a deficient number, since it is larger than the sum of its proper divisors (118430712389).

2013322110307 is a wasteful number, since it uses less digits than its factorization.

2013322110307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118430712388.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 2013322110307 its reverse (7030112233102), we get a palindrome (9043434343409).

The spelling of 2013322110307 in words is "two trillion, thirteen billion, three hundred twenty-two million, one hundred ten thousand, three hundred seven".

Divisors: 1 17 118430712371 2013322110307