Base | Representation |
---|---|
bin | 11101010011000011011… |
… | …011000000101011011001 |
3 | 21010110201222001020222102 |
4 | 131103003123000223121 |
5 | 230441241233113223 |
6 | 4140524042133145 |
7 | 265313012650346 |
oct | 35230333005331 |
9 | 7113658036872 |
10 | 2013323332313 |
11 | 706933596627 |
12 | 286241ab11b5 |
13 | 117b17912c67 |
14 | 6d6341437cd |
15 | 375879eb928 |
hex | 1d4c36c0ad9 |
2013323332313 has 2 divisors, whose sum is σ = 2013323332314. Its totient is φ = 2013323332312.
The previous prime is 2013323332277. The next prime is 2013323332327. The reversal of 2013323332313 is 3132333233102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1559981016064 + 453342316249 = 1248992^2 + 673307^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013323332313 - 218 = 2013323070169 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013323332373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006661666156 + 1006661666157.
It is an arithmetic number, because the mean of its divisors is an integer number (1006661666157).
Almost surely, 22013323332313 is an apocalyptic number.
It is an amenable number.
2013323332313 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013323332313 is an equidigital number, since it uses as much as digits as its factorization.
2013323332313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 29.
Adding to 2013323332313 its reverse (3132333233102), we get a palindrome (5145656565415).
The spelling of 2013323332313 in words is "two trillion, thirteen billion, three hundred twenty-three million, three hundred thirty-two thousand, three hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •