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201333103 = 972075599
BaseRepresentation
bin11000000000000…
…01100101101111
3112000211210002121
430000001211233
5403020124403
631551133411
74663205656
oct1400014557
9460753077
10201333103
11a37135a4
1257514267
133293301a
141ca4c19d
1512a1e3bd
hexc00196f

201333103 has 4 divisors (see below), whose sum is σ = 203408800. Its totient is φ = 199257408.

The previous prime is 201333089. The next prime is 201333131. The reversal of 201333103 is 301333102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201333103 - 221 = 199235951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201333133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1037703 + ... + 1037896.

It is an arithmetic number, because the mean of its divisors is an integer number (50852200).

Almost surely, 2201333103 is an apocalyptic number.

201333103 is a deficient number, since it is larger than the sum of its proper divisors (2075697).

201333103 is an equidigital number, since it uses as much as digits as its factorization.

201333103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2075696.

The product of its (nonzero) digits is 162, while the sum is 16.

The square root of 201333103 is about 14189.1896526898. The cubic root of 201333103 is about 586.1000103043.

Adding to 201333103 its reverse (301333102), we get a palindrome (502666205).

Subtracting 201333103 from its reverse (301333102), we obtain a palindrome (99999999).

The spelling of 201333103 in words is "two hundred one million, three hundred thirty-three thousand, one hundred three".

Divisors: 1 97 2075599 201333103