Base | Representation |
---|---|
bin | 11101010011000011111… |
… | …100000101000101011001 |
3 | 21010110202120100200100002 |
4 | 131103003330011011121 |
5 | 230441300443013423 |
6 | 4140524552022345 |
7 | 265313146433666 |
oct | 35230374050531 |
9 | 7113676320302 |
10 | 2013332001113 |
11 | 706938477624 |
12 | 2862449919b5 |
13 | 117b19659924 |
14 | 6d63535ca6d |
15 | 37588660228 |
hex | 1d4c3f05159 |
2013332001113 has 2 divisors, whose sum is σ = 2013332001114. Its totient is φ = 2013332001112.
The previous prime is 2013332001071. The next prime is 2013332001227. The reversal of 2013332001113 is 3111002333102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1364345474704 + 648986526409 = 1168052^2 + 805597^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013332001113 - 216 = 2013331935577 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013332001913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006666000556 + 1006666000557.
It is an arithmetic number, because the mean of its divisors is an integer number (1006666000557).
Almost surely, 22013332001113 is an apocalyptic number.
It is an amenable number.
2013332001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013332001113 is an equidigital number, since it uses as much as digits as its factorization.
2013332001113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 2013332001113 its reverse (3111002333102), we get a palindrome (5124334334215).
The spelling of 2013332001113 in words is "two trillion, thirteen billion, three hundred thirty-two million, one thousand, one hundred thirteen".
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