Base | Representation |
---|---|
bin | 1011101110000001100… |
… | …1101101110000001001 |
3 | 201020200021012000112011 |
4 | 2323200121231300021 |
5 | 11244312313124001 |
6 | 232254040015521 |
7 | 20355141044143 |
oct | 2734031556011 |
9 | 636607160464 |
10 | 201333333001 |
11 | 78426465aa9 |
12 | 3302a1615a1 |
13 | 15ca7628208 |
14 | 9a5d1dbc93 |
15 | 538554ad51 |
hex | 2ee066dc09 |
201333333001 has 2 divisors, whose sum is σ = 201333333002. Its totient is φ = 201333333000.
The previous prime is 201333332989. The next prime is 201333333011. The reversal of 201333333001 is 100333333102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 139244654025 + 62088678976 = 373155^2 + 249176^2 .
It is a cyclic number.
It is not a de Polignac number, because 201333333001 - 221 = 201331235849 is a prime.
It is a super-2 number, since 2×2013333330012 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201333333011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100666666500 + 100666666501.
It is an arithmetic number, because the mean of its divisors is an integer number (100666666501).
Almost surely, 2201333333001 is an apocalyptic number.
It is an amenable number.
201333333001 is a deficient number, since it is larger than the sum of its proper divisors (1).
201333333001 is an equidigital number, since it uses as much as digits as its factorization.
201333333001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 22.
Adding to 201333333001 its reverse (100333333102), we get a palindrome (301666666103).
The spelling of 201333333001 in words is "two hundred one billion, three hundred thirty-three million, three hundred thirty-three thousand, one".
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