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201333340132 = 22232188405871
BaseRepresentation
bin1011101110000001100…
…1101111011111100100
3201020200021012101022021
42323200121233133210
511244312313341012
6232254040112524
720355141104011
oct2734031573744
9636607171267
10201333340132
11784264703a1
123302a165744
1315ca762b532
149a5d200708
15538554d007
hex2ee066f7e4

201333340132 has 12 divisors (see below), whose sum is σ = 367652186496. Its totient is φ = 96289858280.

The previous prime is 201333340123. The next prime is 201333340141. The reversal of 201333340132 is 231043333102.

It is an interprime number because it is at equal distance from previous prime (201333340123) and next prime (201333340141).

It is a super-2 number, since 2×2013333401322 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201333340097 and 201333340106.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1094202844 + ... + 1094203027.

It is an arithmetic number, because the mean of its divisors is an integer number (30637682208).

Almost surely, 2201333340132 is an apocalyptic number.

It is an amenable number.

201333340132 is a deficient number, since it is larger than the sum of its proper divisors (166318846364).

201333340132 is a wasteful number, since it uses less digits than its factorization.

201333340132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2188405898 (or 2188405896 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 201333340132 its reverse (231043333102), we get a palindrome (432376673234).

The spelling of 201333340132 in words is "two hundred one billion, three hundred thirty-three million, three hundred forty thousand, one hundred thirty-two".

Divisors: 1 2 4 23 46 92 2188405871 4376811742 8753623484 50333335033 100666670066 201333340132