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2013343140103 = 107181103957409
BaseRepresentation
bin11101010011000100100…
…110100100100100000111
321010110210100022121011021
4131103010212210210013
5230441311320440403
64140530030452011
7265313343216121
oct35230446444407
97113710277137
102013343140103
117069437954a9
12286248664007
13117b1ba59a49
146d636a1c211
15375896108bd
hex1d4c49a4907

2013343140103 has 8 divisors (see below), whose sum is σ = 2043386850960. Its totient is φ = 1983507344640.

The previous prime is 2013343140097. The next prime is 2013343140169. The reversal of 2013343140103 is 3010413433102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013343140103 - 229 = 2012806269191 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013343140503) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51959338 + ... + 51998071.

It is an arithmetic number, because the mean of its divisors is an integer number (255423356370).

Almost surely, 22013343140103 is an apocalyptic number.

2013343140103 is a deficient number, since it is larger than the sum of its proper divisors (30043710857).

2013343140103 is a wasteful number, since it uses less digits than its factorization.

2013343140103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103957697.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 2013343140103 its reverse (3010413433102), we get a palindrome (5023756573205).

The spelling of 2013343140103 in words is "two trillion, thirteen billion, three hundred forty-three million, one hundred forty thousand, one hundred three".

Divisors: 1 107 181 19367 103957409 11123442763 18816291029 2013343140103