Base | Representation |
---|---|
bin | 11101010011000100101… |
… | …101111010011000110011 |
3 | 21010110210110221100221012 |
4 | 131103010231322120303 |
5 | 230441312314030444 |
6 | 4140530140021135 |
7 | 265313365452446 |
oct | 35230455723063 |
9 | 7113713840835 |
10 | 2013345064499 |
11 | 70694488a30a |
12 | 2862492317ab |
13 | 117b1c281942 |
14 | 6d636d9d65d |
15 | 37589890b9e |
hex | 1d4c4b7a633 |
2013345064499 has 2 divisors, whose sum is σ = 2013345064500. Its totient is φ = 2013345064498.
The previous prime is 2013345064487. The next prime is 2013345064571. The reversal of 2013345064499 is 9944605433102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013345064499 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013345064429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006672532249 + 1006672532250.
It is an arithmetic number, because the mean of its divisors is an integer number (1006672532250).
Almost surely, 22013345064499 is an apocalyptic number.
2013345064499 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013345064499 is an equidigital number, since it uses as much as digits as its factorization.
2013345064499 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2799360, while the sum is 50.
The spelling of 2013345064499 in words is "two trillion, thirteen billion, three hundred forty-five million, sixty-four thousand, four hundred ninety-nine".
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