Base | Representation |
---|---|
bin | 11101010011000100110… |
… | …011001111000111101001 |
3 | 21010110210120120021101111 |
4 | 131103010303033013221 |
5 | 230441313143211022 |
6 | 4140530225550321 |
7 | 265313413354405 |
oct | 35230463170751 |
9 | 7113716507344 |
10 | 2013346460137 |
11 | 706945652931 |
12 | 2862497a53a1 |
13 | 117b1c64cc6c |
14 | 6d637244105 |
15 | 37589a69477 |
hex | 1d4c4ccf1e9 |
2013346460137 has 2 divisors, whose sum is σ = 2013346460138. Its totient is φ = 2013346460136.
The previous prime is 2013346460123. The next prime is 2013346460179. The reversal of 2013346460137 is 7310646433102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1644188143081 + 369158317056 = 1282259^2 + 607584^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013346460137 - 27 = 2013346460009 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2013346460137.
It is not a weakly prime, because it can be changed into another prime (2013346460197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006673230068 + 1006673230069.
It is an arithmetic number, because the mean of its divisors is an integer number (1006673230069).
Almost surely, 22013346460137 is an apocalyptic number.
It is an amenable number.
2013346460137 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013346460137 is an equidigital number, since it uses as much as digits as its factorization.
2013346460137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 217728, while the sum is 40.
The spelling of 2013346460137 in words is "two trillion, thirteen billion, three hundred forty-six million, four hundred sixty thousand, one hundred thirty-seven".
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