201340121 has 2 divisors, whose sum is σ = 201340122. Its totient is φ = 201340120.

The previous prime is 201340103. The next prime is 201340141. The reversal of 201340121 is 121043102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 184824025 + 16516096 = 13595^2 + 4064^2 .

It is a cyclic number.

It is not a de Polignac number, because 201340121 - 2¹⁴ = 201323737 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 201340096 and 201340105.

It is not a weakly prime, because it can be changed into another prime (201340141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670060 + 100670061.

It is an arithmetic number, because the mean of its divisors is an integer number (100670061).

Almost surely, 2^201340121 is an apocalyptic number.

It is an amenable number.

201340121 is a deficient number, since it is larger than the sum of its proper divisors (1).

201340121 is an equidigital number, since it uses as much as digits as its factorization.

201340121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 201340121 is about 14189.4369514791. The cubic root of 201340121 is about 586.1068202493.

Adding to 201340121 its reverse (121043102), we get a palindrome (322383223).

The spelling of 201340121 in words is "two hundred one million, three hundred forty thousand, one hundred twenty-one".