Base | Representation |
---|---|
bin | 10010110000000101… |
… | …001100100100111001 |
3 | 1220222011201021002112 |
4 | 102300011030210321 |
5 | 312213302141213 |
6 | 13125513542105 |
7 | 1311640233641 |
oct | 226005144471 |
9 | 56864637075 |
10 | 20134021433 |
11 | 85a2148339 |
12 | 3a9aa14935 |
13 | 1b8b3a0966 |
14 | d90011521 |
15 | 7cc8e0ea8 |
hex | 4b014c939 |
20134021433 has 2 divisors, whose sum is σ = 20134021434. Its totient is φ = 20134021432.
The previous prime is 20134021409. The next prime is 20134021463. The reversal of 20134021433 is 33412043102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18935961664 + 1198059769 = 137608^2 + 34613^2 .
It is a cyclic number.
It is not a de Polignac number, because 20134021433 - 210 = 20134020409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20134021399 and 20134021408.
It is not a weakly prime, because it can be changed into another prime (20134021463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067010716 + 10067010717.
It is an arithmetic number, because the mean of its divisors is an integer number (10067010717).
Almost surely, 220134021433 is an apocalyptic number.
It is an amenable number.
20134021433 is a deficient number, since it is larger than the sum of its proper divisors (1).
20134021433 is an equidigital number, since it uses as much as digits as its factorization.
20134021433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 20134021433 its reverse (33412043102), we get a palindrome (53546064535).
The spelling of 20134021433 in words is "twenty billion, one hundred thirty-four million, twenty-one thousand, four hundred thirty-three".
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