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20134021433 is a prime number
BaseRepresentation
bin10010110000000101…
…001100100100111001
31220222011201021002112
4102300011030210321
5312213302141213
613125513542105
71311640233641
oct226005144471
956864637075
1020134021433
1185a2148339
123a9aa14935
131b8b3a0966
14d90011521
157cc8e0ea8
hex4b014c939

20134021433 has 2 divisors, whose sum is σ = 20134021434. Its totient is φ = 20134021432.

The previous prime is 20134021409. The next prime is 20134021463. The reversal of 20134021433 is 33412043102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18935961664 + 1198059769 = 137608^2 + 34613^2 .

It is a cyclic number.

It is not a de Polignac number, because 20134021433 - 210 = 20134020409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20134021399 and 20134021408.

It is not a weakly prime, because it can be changed into another prime (20134021463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067010716 + 10067010717.

It is an arithmetic number, because the mean of its divisors is an integer number (10067010717).

Almost surely, 220134021433 is an apocalyptic number.

It is an amenable number.

20134021433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20134021433 is an equidigital number, since it uses as much as digits as its factorization.

20134021433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 20134021433 its reverse (33412043102), we get a palindrome (53546064535).

The spelling of 20134021433 in words is "twenty billion, one hundred thirty-four million, twenty-one thousand, four hundred thirty-three".