Base | Representation |
---|---|
bin | 11101010011001000001… |
… | …000010010111000100111 |
3 | 21010110221110122212001120 |
4 | 131103020020102320213 |
5 | 230441421442442411 |
6 | 4140535543025023 |
7 | 265314662164452 |
oct | 35231010227047 |
9 | 7113843585046 |
10 | 2013402312231 |
11 | 706974130392 |
12 | 28626443b173 |
13 | 117b2b0a6c3b |
14 | 6d640822499 |
15 | 3758e8ed106 |
hex | 1d4c8212e27 |
2013402312231 has 16 divisors (see below), whose sum is σ = 2923270147200. Its totient is φ = 1227773459808.
The previous prime is 2013402312217. The next prime is 2013402312239. The reversal of 2013402312231 is 1322132043102.
It is not a de Polignac number, because 2013402312231 - 26 = 2013402312167 is a prime.
It is a super-2 number, since 2×20134023122312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013402312239) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 609012961 + ... + 609016266.
It is an arithmetic number, because the mean of its divisors is an integer number (182704384200).
Almost surely, 22013402312231 is an apocalyptic number.
2013402312231 is a deficient number, since it is larger than the sum of its proper divisors (909867834969).
2013402312231 is a wasteful number, since it uses less digits than its factorization.
2013402312231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1218029278.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 2013402312231 its reverse (1322132043102), we get a palindrome (3335534355333).
The spelling of 2013402312231 in words is "two trillion, thirteen billion, four hundred two million, three hundred twelve thousand, two hundred thirty-one".
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