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20134025223415 = 534785091136379
BaseRepresentation
bin1001001001111110100010…
…11010111101110011110111
32122021210102211120021202021
410210333101122331303313
510114333440424122130
6110453235443454011
74145430625435315
oct444772132756367
978253384507667
1020134025223415
116462879389094
122312138387307
13b3082709ba6c
144d86c61650b5
1524daeb2a337a
hex124fd16bdcf7

20134025223415 has 16 divisors (see below), whose sum is σ = 24230920452480. Its totient is φ = 16060495163680.

The previous prime is 20134025223401. The next prime is 20134025223467. The reversal of 20134025223415 is 51432252043102.

It is not a de Polignac number, because 20134025223415 - 29 = 20134025222903 is a prime.

It is a super-2 number, since 2×201340252234152 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 147564696 + ... + 147701074.

It is an arithmetic number, because the mean of its divisors is an integer number (1514432528280).

Almost surely, 220134025223415 is an apocalyptic number.

20134025223415 is a deficient number, since it is larger than the sum of its proper divisors (4096895229065).

20134025223415 is a wasteful number, since it uses less digits than its factorization.

20134025223415 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221822.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 20134025223415 its reverse (51432252043102), we get a palindrome (71566277266517).

The spelling of 20134025223415 in words is "twenty trillion, one hundred thirty-four billion, twenty-five million, two hundred twenty-three thousand, four hundred fifteen".

Divisors: 1 5 347 1735 85091 136379 425455 681895 29526577 47323513 147632885 236617565 11604625489 58023127445 4026805044683 20134025223415