Base | Representation |
---|---|
bin | 10010110000000101… |
… | …100101111111011111 |
3 | 1220222011220112220011 |
4 | 102300011211333133 |
5 | 312213314004120 |
6 | 13125520104051 |
7 | 1311641146306 |
oct | 226005457737 |
9 | 56864815804 |
10 | 20134125535 |
11 | 85a2209577 |
12 | 3a9aa65027 |
13 | 1b8b409164 |
14 | d9003b43d |
15 | 7cc911c5a |
hex | 4b0165fdf |
20134125535 has 32 divisors (see below), whose sum is σ = 25293772800. Its totient is φ = 15370185600.
The previous prime is 20134125527. The next prime is 20134125563. The reversal of 20134125535 is 53552143102.
It is not a de Polignac number, because 20134125535 - 23 = 20134125527 is a prime.
It is a super-2 number, since 2×201341255352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20134125497 and 20134125506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5226360 + ... + 5230210.
It is an arithmetic number, because the mean of its divisors is an integer number (790430400).
Almost surely, 220134125535 is an apocalyptic number.
20134125535 is a deficient number, since it is larger than the sum of its proper divisors (5159647265).
20134125535 is a wasteful number, since it uses less digits than its factorization.
20134125535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4431.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 20134125535 its reverse (53552143102), we get a palindrome (73686268637).
The spelling of 20134125535 in words is "twenty billion, one hundred thirty-four million, one hundred twenty-five thousand, five hundred thirty-five".
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