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2013413504251 is a prime number
BaseRepresentation
bin11101010011001000110…
…010111111010011111011
321010110222020201110121211
4131103020302333103323
5230441432324114001
64140541022543551
7265315156260322
oct35231062772373
97113866643554
102013413504251
1170697a485096
12286268137bb7
13117b304c5236
146d6420d70b9
15375908ae351
hex1d4c8cbf4fb

2013413504251 has 2 divisors, whose sum is σ = 2013413504252. Its totient is φ = 2013413504250.

The previous prime is 2013413504237. The next prime is 2013413504261. The reversal of 2013413504251 is 1524053143102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2013413504251 - 221 = 2013411407099 is a prime.

It is not a weakly prime, because it can be changed into another prime (2013413504261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006706752125 + 1006706752126.

It is an arithmetic number, because the mean of its divisors is an integer number (1006706752126).

Almost surely, 22013413504251 is an apocalyptic number.

2013413504251 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013413504251 is an equidigital number, since it uses as much as digits as its factorization.

2013413504251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 2013413504251 its reverse (1524053143102), we get a palindrome (3537466647353).

The spelling of 2013413504251 in words is "two trillion, thirteen billion, four hundred thirteen million, five hundred four thousand, two hundred fifty-one".