Base | Representation |
---|---|
bin | 11101010011001001010… |
… | …011110100110111100111 |
3 | 21010110222211220210112220 |
4 | 131103021103310313213 |
5 | 230441442030042411 |
6 | 4140541531243423 |
7 | 265315322401425 |
oct | 35231123646747 |
9 | 7113884823486 |
10 | 2013422112231 |
11 | 706984324422 |
12 | 28626aba9573 |
13 | 117b3221a30a |
14 | 6d6432d8115 |
15 | 3759150eb06 |
hex | 1d4c94f4de7 |
2013422112231 has 8 divisors (see below), whose sum is σ = 2684601514224. Its totient is φ = 1342262059200.
The previous prime is 2013422112217. The next prime is 2013422112257. The reversal of 2013422112231 is 1322112243102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2013422112231 - 27 = 2013422112103 is a prime.
It is a super-2 number, since 2×20134221122312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013422111231) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4592670 + ... + 5011931.
It is an arithmetic number, because the mean of its divisors is an integer number (335575189278).
Almost surely, 22013422112231 is an apocalyptic number.
2013422112231 is a deficient number, since it is larger than the sum of its proper divisors (671179401993).
2013422112231 is an equidigital number, since it uses as much as digits as its factorization.
2013422112231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9674481.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 2013422112231 its reverse (1322112243102), we get a palindrome (3335534355333).
The spelling of 2013422112231 in words is "two trillion, thirteen billion, four hundred twenty-two million, one hundred twelve thousand, two hundred thirty-one".
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