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20134223413 = 51013947113
BaseRepresentation
bin10010110000000101…
…111101111000110101
31220222012002112011021
4102300011331320311
5312213330122123
613125522141141
71311642034543
oct226005757065
956865075137
1020134223413
1185a2276067
123a9aab17b1
131b8b441885
14d90064d93
157cc930c5d
hex4b017de35

20134223413 has 4 divisors (see below), whose sum is σ = 20138175628. Its totient is φ = 20130271200.

The previous prime is 20134223407. The next prime is 20134223423. The reversal of 20134223413 is 31432243102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 706602724 + 19427620689 = 26582^2 + 139383^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20134223413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20134223423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1968456 + ... + 1978657.

It is an arithmetic number, because the mean of its divisors is an integer number (5034543907).

Almost surely, 220134223413 is an apocalyptic number.

It is an amenable number.

20134223413 is a deficient number, since it is larger than the sum of its proper divisors (3952215).

20134223413 is an equidigital number, since it uses as much as digits as its factorization.

20134223413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3952214.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 20134223413 its reverse (31432243102), we get a palindrome (51566466515).

The spelling of 20134223413 in words is "twenty billion, one hundred thirty-four million, two hundred twenty-three thousand, four hundred thirteen".

Divisors: 1 5101 3947113 20134223413