Base | Representation |
---|---|
bin | 1011101110000011111… |
… | …0101000010111010001 |
3 | 201020200221101200020001 |
4 | 2323200332220113101 |
5 | 11244322302312012 |
6 | 232255023250001 |
7 | 20355316230544 |
oct | 2734076502721 |
9 | 636627350201 |
10 | 201343010257 |
11 | 78430975734 |
12 | 33031449901 |
13 | 15ca9635bbc |
14 | 9a605da85b |
15 | 538630d357 |
hex | 2ee0fa85d1 |
201343010257 has 2 divisors, whose sum is σ = 201343010258. Its totient is φ = 201343010256.
The previous prime is 201343010249. The next prime is 201343010287. The reversal of 201343010257 is 752010343102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 191457878481 + 9885131776 = 437559^2 + 99424^2 .
It is a cyclic number.
It is not a de Polignac number, because 201343010257 - 23 = 201343010249 is a prime.
It is a super-3 number, since 3×2013430102573 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (201343010287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100671505128 + 100671505129.
It is an arithmetic number, because the mean of its divisors is an integer number (100671505129).
Almost surely, 2201343010257 is an apocalyptic number.
It is an amenable number.
201343010257 is a deficient number, since it is larger than the sum of its proper divisors (1).
201343010257 is an equidigital number, since it uses as much as digits as its factorization.
201343010257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 28.
Adding to 201343010257 its reverse (752010343102), we get a palindrome (953353353359).
The spelling of 201343010257 in words is "two hundred one billion, three hundred forty-three million, ten thousand, two hundred fifty-seven".
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