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201343399981 = 375441713513
BaseRepresentation
bin1011101110000100000…
…0000111100000101101
3201020200222010110211021
42323201000013200231
511244322402244411
6232255035454141
720355322443013
oct2734100074055
9636628113737
10201343399981
1178431111519
12330315b7351
1315ca97413c9
149a6069c8b3
155386388a71
hex2ee100782d

201343399981 has 4 divisors (see below), whose sum is σ = 206785113532. Its totient is φ = 195901686432.

The previous prime is 201343399967. The next prime is 201343400017. The reversal of 201343399981 is 189993343102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 80594099881 + 120749300100 = 283891^2 + 347490^2 .

It is a cyclic number.

It is not a de Polignac number, because 201343399981 - 25 = 201343399949 is a prime.

It is a super-2 number, since 2×2013433999812 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201343396981) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2720856720 + ... + 2720856793.

It is an arithmetic number, because the mean of its divisors is an integer number (51696278383).

Almost surely, 2201343399981 is an apocalyptic number.

It is an amenable number.

201343399981 is a deficient number, since it is larger than the sum of its proper divisors (5441713551).

201343399981 is an equidigital number, since it uses as much as digits as its factorization.

201343399981 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5441713550.

The product of its (nonzero) digits is 1259712, while the sum is 52.

The spelling of 201343399981 in words is "two hundred one billion, three hundred forty-three million, three hundred ninety-nine thousand, nine hundred eighty-one".

Divisors: 1 37 5441713513 201343399981