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201343411113371 is a prime number
BaseRepresentation
bin101101110001111011101010…
…011111110100110110011011
3222101220020112111122120011022
4231301323222133310312123
5202342302301221111441
61552115515223553055
760260403265342022
oct5561735237646633
9871806474576138
10201343411113371
115917729661a53a
121a6b9850bbb78b
1388467aa052c47
1437a11047db8b9
15184260e19b84b
hexb71eea7f4d9b

201343411113371 has 2 divisors, whose sum is σ = 201343411113372. Its totient is φ = 201343411113370.

The previous prime is 201343411113331. The next prime is 201343411113451. The reversal of 201343411113371 is 173311114343102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201343411113371 - 26 = 201343411113307 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (201343411113331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100671705556685 + 100671705556686.

It is an arithmetic number, because the mean of its divisors is an integer number (100671705556686).

Almost surely, 2201343411113371 is an apocalyptic number.

201343411113371 is a deficient number, since it is larger than the sum of its proper divisors (1).

201343411113371 is an equidigital number, since it uses as much as digits as its factorization.

201343411113371 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 35.

Adding to 201343411113371 its reverse (173311114343102), we get a palindrome (374654525456473).

The spelling of 201343411113371 in words is "two hundred one trillion, three hundred forty-three billion, four hundred eleven million, one hundred thirteen thousand, three hundred seventy-one".