Base | Representation |
---|---|
bin | 101101110001111011101010… |
… | …011111110100110110011011 |
3 | 222101220020112111122120011022 |
4 | 231301323222133310312123 |
5 | 202342302301221111441 |
6 | 1552115515223553055 |
7 | 60260403265342022 |
oct | 5561735237646633 |
9 | 871806474576138 |
10 | 201343411113371 |
11 | 5917729661a53a |
12 | 1a6b9850bbb78b |
13 | 88467aa052c47 |
14 | 37a11047db8b9 |
15 | 184260e19b84b |
hex | b71eea7f4d9b |
201343411113371 has 2 divisors, whose sum is σ = 201343411113372. Its totient is φ = 201343411113370.
The previous prime is 201343411113331. The next prime is 201343411113451. The reversal of 201343411113371 is 173311114343102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201343411113371 - 26 = 201343411113307 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (201343411113331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100671705556685 + 100671705556686.
It is an arithmetic number, because the mean of its divisors is an integer number (100671705556686).
Almost surely, 2201343411113371 is an apocalyptic number.
201343411113371 is a deficient number, since it is larger than the sum of its proper divisors (1).
201343411113371 is an equidigital number, since it uses as much as digits as its factorization.
201343411113371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 35.
Adding to 201343411113371 its reverse (173311114343102), we get a palindrome (374654525456473).
The spelling of 201343411113371 in words is "two hundred one trillion, three hundred forty-three billion, four hundred eleven million, one hundred thirteen thousand, three hundred seventy-one".
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