Base | Representation |
---|---|
bin | 1001001010000000011011… |
… | …00001010110101011111111 |
3 | 2122021220001002212121220122 |
4 | 10211000031201112223333 |
5 | 10114343022040444020 |
6 | 110453523503205155 |
7 | 4145464621060055 |
oct | 445001541265377 |
9 | 78256032777818 |
10 | 20135033531135 |
11 | 6463246566656 |
12 | 2312379ba67bb |
13 | b30957c57453 |
14 | 4d87800361d5 |
15 | 24db59a76125 |
hex | 12500d856aff |
20135033531135 has 32 divisors (see below), whose sum is σ = 24816767688000. Its totient is φ = 15677015065600.
The previous prime is 20135033531099. The next prime is 20135033531141. The reversal of 20135033531135 is 53113533053102.
It is a de Polignac number, because none of the positive numbers 2k-20135033531135 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20135033531095 and 20135033531104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 701628107 + ... + 701656803.
It is an arithmetic number, because the mean of its divisors is an integer number (775523990250).
Almost surely, 220135033531135 is an apocalyptic number.
20135033531135 is a deficient number, since it is larger than the sum of its proper divisors (4681734156865).
20135033531135 is a wasteful number, since it uses less digits than its factorization.
20135033531135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52411.
The product of its (nonzero) digits is 60750, while the sum is 35.
Adding to 20135033531135 its reverse (53113533053102), we get a palindrome (73248566584237).
The spelling of 20135033531135 in words is "twenty trillion, one hundred thirty-five billion, thirty-three million, five hundred thirty-one thousand, one hundred thirty-five".
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