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20135075757481 is a prime number
BaseRepresentation
bin1001001010000000100000…
…00010011011110110101001
32122021220011001022221120101
410211000100002123312221
510114343113343214411
6110453532012225401
74145465643016666
oct445002002336651
978256131287511
1020135075757481
116463268387963
12231239016b261
13b30963920459
144d87858a8a6d
1524db5d6178c1
hex12501009bda9

20135075757481 has 2 divisors, whose sum is σ = 20135075757482. Its totient is φ = 20135075757480.

The previous prime is 20135075757473. The next prime is 20135075757487. The reversal of 20135075757481 is 18475757053102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16212774727081 + 3922301030400 = 4026509^2 + 1980480^2 .

It is a cyclic number.

It is not a de Polignac number, because 20135075757481 - 23 = 20135075757473 is a prime.

It is a super-3 number, since 3×201350757574813 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (20135075757487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067537878740 + 10067537878741.

It is an arithmetic number, because the mean of its divisors is an integer number (10067537878741).

Almost surely, 220135075757481 is an apocalyptic number.

It is an amenable number.

20135075757481 is a deficient number, since it is larger than the sum of its proper divisors (1).

20135075757481 is an equidigital number, since it uses as much as digits as its factorization.

20135075757481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8232000, while the sum is 55.

The spelling of 20135075757481 in words is "twenty trillion, one hundred thirty-five billion, seventy-five million, seven hundred fifty-seven thousand, four hundred eighty-one".