Base | Representation |
---|---|
bin | 1001001010000000101001… |
… | …01011001011100111111011 |
3 | 2122021220100110201002210020 |
4 | 10211000110223023213323 |
5 | 10114343243302012041 |
6 | 110453543431421523 |
7 | 4145500606150563 |
oct | 445002453134773 |
9 | 78256313632706 |
10 | 20135153547771 |
11 | 64632a8289959 |
12 | 23123b22248a3 |
13 | b30976a88b02 |
14 | 4d8791d57da3 |
15 | 24db65381866 |
hex | 125014acb9fb |
20135153547771 has 8 divisors (see below), whose sum is σ = 27418081426944. Its totient is φ = 13137830683560.
The previous prime is 20135153547749. The next prime is 20135153547809. The reversal of 20135153547771 is 17774535153102.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20135153547771 - 215 = 20135153515003 is a prime.
It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is not an unprimeable number, because it can be changed into a prime (20135153547571) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71401253575 + ... + 71401253856.
It is an arithmetic number, because the mean of its divisors is an integer number (3427260178368).
Almost surely, 220135153547771 is an apocalyptic number.
20135153547771 is a deficient number, since it is larger than the sum of its proper divisors (7282927879173).
20135153547771 is a wasteful number, since it uses less digits than its factorization.
20135153547771 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142802507481.
The product of its (nonzero) digits is 3087000, while the sum is 51.
The spelling of 20135153547771 in words is "twenty trillion, one hundred thirty-five billion, one hundred fifty-three million, five hundred forty-seven thousand, seven hundred seventy-one".
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