Base | Representation |
---|---|
bin | 1001001010000001100010… |
… | …00110101111100111111001 |
3 | 2122021221120201020120110212 |
4 | 10211000301012233213321 |
5 | 10114400232404111121 |
6 | 110454103031120505 |
7 | 4145515460400431 |
oct | 445006106574771 |
9 | 78257521216425 |
10 | 20135630535161 |
11 | 6463522558609 |
12 | 2312505b13135 |
13 | b30a2184447b |
14 | 4d87d943d2c1 |
15 | 24db921a125b |
hex | 1250311af9f9 |
20135630535161 has 2 divisors, whose sum is σ = 20135630535162. Its totient is φ = 20135630535160.
The previous prime is 20135630535113. The next prime is 20135630535179. The reversal of 20135630535161 is 16153503653102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16790170051561 + 3345460483600 = 4097581^2 + 1829060^2 .
It is a cyclic number.
It is not a de Polignac number, because 20135630535161 - 214 = 20135630518777 is a prime.
It is not a weakly prime, because it can be changed into another prime (20135630535101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067815267580 + 10067815267581.
It is an arithmetic number, because the mean of its divisors is an integer number (10067815267581).
Almost surely, 220135630535161 is an apocalyptic number.
It is an amenable number.
20135630535161 is a deficient number, since it is larger than the sum of its proper divisors (1).
20135630535161 is an equidigital number, since it uses as much as digits as its factorization.
20135630535161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243000, while the sum is 41.
The spelling of 20135630535161 in words is "twenty trillion, one hundred thirty-five billion, six hundred thirty million, five hundred thirty-five thousand, one hundred sixty-one".
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