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2013603043873 is a prime number
BaseRepresentation
bin11101010011010100000…
…110000001101000100001
321010111110110101002002211
4131103110012001220201
5230442324334400443
64141011513242121
7265322650320061
oct35232406015041
97114413332084
102013603043873
11706a67473003
122862bb703341
13117b60859265
146d65d3553a1
15375a234e19d
hex1d4d4181a21

2013603043873 has 2 divisors, whose sum is σ = 2013603043874. Its totient is φ = 2013603043872.

The previous prime is 2013603043813. The next prime is 2013603043891. The reversal of 2013603043873 is 3783403063102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2004214984209 + 9388059664 = 1415703^2 + 96892^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013603043873 is a prime.

It is a super-2 number, since 2×20136030438732 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2013603043813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006801521936 + 1006801521937.

It is an arithmetic number, because the mean of its divisors is an integer number (1006801521937).

Almost surely, 22013603043873 is an apocalyptic number.

It is an amenable number.

2013603043873 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013603043873 is an equidigital number, since it uses as much as digits as its factorization.

2013603043873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 40.

The spelling of 2013603043873 in words is "two trillion, thirteen billion, six hundred three million, forty-three thousand, eight hundred seventy-three".