Base | Representation |
---|---|
bin | 1011101110010001110… |
… | …1011011001010011101 |
3 | 201020212000021220111210 |
4 | 2323210131123022131 |
5 | 11244432230224201 |
6 | 232304511135033 |
7 | 20356625526663 |
oct | 2734435331235 |
9 | 636760256453 |
10 | 201401414301 |
11 | 7846093653a |
12 | 33048b14479 |
13 | 15cb87745c9 |
14 | 9a68280c33 |
15 | 538b4e81d6 |
hex | 2ee475b29d |
201401414301 has 4 divisors (see below), whose sum is σ = 268535219072. Its totient is φ = 134267609532.
The previous prime is 201401414293. The next prime is 201401414317. The reversal of 201401414301 is 103414104102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 201401414301 - 23 = 201401414293 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201401414381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33566902381 + ... + 33566902386.
It is an arithmetic number, because the mean of its divisors is an integer number (67133804768).
Almost surely, 2201401414301 is an apocalyptic number.
It is an amenable number.
201401414301 is a deficient number, since it is larger than the sum of its proper divisors (67133804771).
201401414301 is an equidigital number, since it uses as much as digits as its factorization.
201401414301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67133804770.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 201401414301 its reverse (103414104102), we get a palindrome (304815518403).
The spelling of 201401414301 in words is "two hundred one billion, four hundred one million, four hundred fourteen thousand, three hundred one".
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