Base | Representation |
---|---|
bin | 1011101110010001110… |
… | …1011011001010010101 |
3 | 201020212000021220111111 |
4 | 2323210131123022111 |
5 | 11244432230224133 |
6 | 232304511135021 |
7 | 20356625526652 |
oct | 2734435331225 |
9 | 636760256444 |
10 | 201401414293 |
11 | 78460936532 |
12 | 33048b14471 |
13 | 15cb87745c1 |
14 | 9a68280c29 |
15 | 538b4e81cd |
hex | 2ee475b295 |
201401414293 has 2 divisors, whose sum is σ = 201401414294. Its totient is φ = 201401414292.
The previous prime is 201401414281. The next prime is 201401414317. The reversal of 201401414293 is 392414104102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 193302674244 + 8098740049 = 439662^2 + 89993^2 .
It is a cyclic number.
It is not a de Polignac number, because 201401414293 - 25 = 201401414261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201401414213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100700707146 + 100700707147.
It is an arithmetic number, because the mean of its divisors is an integer number (100700707147).
Almost surely, 2201401414293 is an apocalyptic number.
It is an amenable number.
201401414293 is a deficient number, since it is larger than the sum of its proper divisors (1).
201401414293 is an equidigital number, since it uses as much as digits as its factorization.
201401414293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 201401414293 its reverse (392414104102), we get a palindrome (593815518395).
The spelling of 201401414293 in words is "two hundred one billion, four hundred one million, four hundred fourteen thousand, two hundred ninety-three".
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