Search a number
-
+
201401414293 is a prime number
BaseRepresentation
bin1011101110010001110…
…1011011001010010101
3201020212000021220111111
42323210131123022111
511244432230224133
6232304511135021
720356625526652
oct2734435331225
9636760256444
10201401414293
1178460936532
1233048b14471
1315cb87745c1
149a68280c29
15538b4e81cd
hex2ee475b295

201401414293 has 2 divisors, whose sum is σ = 201401414294. Its totient is φ = 201401414292.

The previous prime is 201401414281. The next prime is 201401414317. The reversal of 201401414293 is 392414104102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 193302674244 + 8098740049 = 439662^2 + 89993^2 .

It is a cyclic number.

It is not a de Polignac number, because 201401414293 - 25 = 201401414261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201401414213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100700707146 + 100700707147.

It is an arithmetic number, because the mean of its divisors is an integer number (100700707147).

Almost surely, 2201401414293 is an apocalyptic number.

It is an amenable number.

201401414293 is a deficient number, since it is larger than the sum of its proper divisors (1).

201401414293 is an equidigital number, since it uses as much as digits as its factorization.

201401414293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 201401414293 its reverse (392414104102), we get a palindrome (593815518395).

The spelling of 201401414293 in words is "two hundred one billion, four hundred one million, four hundred fourteen thousand, two hundred ninety-three".