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2014022041561 is a prime number
BaseRepresentation
bin11101010011101101000…
…100010111111111011001
321010112112122210100212201
4131103231010113333121
5230444204120312221
64141121242010201
7265336225614505
oct35235504277731
97115478710781
102014022041561
11707161a34192
122863b7aa6961
13117bc95bc99a
146d69cc63305
15375c9016891
hex1d4ed117fd9

2014022041561 has 2 divisors, whose sum is σ = 2014022041562. Its totient is φ = 2014022041560.

The previous prime is 2014022041541. The next prime is 2014022041567. The reversal of 2014022041561 is 1651402204102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1431480638025 + 582541403536 = 1196445^2 + 763244^2 .

It is a cyclic number.

It is not a de Polignac number, because 2014022041561 - 215 = 2014022008793 is a prime.

It is a super-2 number, since 2×20140220415612 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2014022041567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007011020780 + 1007011020781.

It is an arithmetic number, because the mean of its divisors is an integer number (1007011020781).

Almost surely, 22014022041561 is an apocalyptic number.

It is an amenable number.

2014022041561 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014022041561 is an equidigital number, since it uses as much as digits as its factorization.

2014022041561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 2014022041561 its reverse (1651402204102), we get a palindrome (3665424245663).

The spelling of 2014022041561 in words is "two trillion, fourteen billion, twenty-two million, forty-one thousand, five hundred sixty-one".