Base | Representation |
---|---|
bin | 1011101110010011111… |
… | …0100111001000000011 |
3 | 201020212121122220022202 |
4 | 2323210332213020003 |
5 | 11244441442122201 |
6 | 232305421423415 |
7 | 20360062502456 |
oct | 2734476471003 |
9 | 636777586282 |
10 | 201410114051 |
11 | 78465838813 |
12 | 3304ba0ab6b |
13 | 15cba4cc3a3 |
14 | 9a694a749d |
15 | 538c165c6b |
hex | 2ee4fa7203 |
201410114051 has 2 divisors, whose sum is σ = 201410114052. Its totient is φ = 201410114050.
The previous prime is 201410114047. The next prime is 201410114077. The reversal of 201410114051 is 150411014102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201410114051 - 22 = 201410114047 is a prime.
It is not a weakly prime, because it can be changed into another prime (201410116051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100705057025 + 100705057026.
It is an arithmetic number, because the mean of its divisors is an integer number (100705057026).
Almost surely, 2201410114051 is an apocalyptic number.
201410114051 is a deficient number, since it is larger than the sum of its proper divisors (1).
201410114051 is an equidigital number, since it uses as much as digits as its factorization.
201410114051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160, while the sum is 20.
Adding to 201410114051 its reverse (150411014102), we get a palindrome (351821128153).
The spelling of 201410114051 in words is "two hundred one billion, four hundred ten million, one hundred fourteen thousand, fifty-one".
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