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2014102023 = 33121657011
BaseRepresentation
bin111100000001100…
…1100001000000111
312012100212222120020
41320003030020013
513111102231043
6531505110223
7100624404363
oct17003141007
95170788506
102014102023
119439a972a
12482628373
1326137405b
141516ca2a3
15bbc4ae83
hex780cc207

2014102023 has 8 divisors (see below), whose sum is σ = 2772097536. Its totient is φ = 1299420600.

The previous prime is 2014102007. The next prime is 2014102031. The reversal of 2014102023 is 3202014102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2014102023 - 24 = 2014102007 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2014101993 and 2014102011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2014102423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10828413 + ... + 10828598.

It is an arithmetic number, because the mean of its divisors is an integer number (346512192).

Almost surely, 22014102023 is an apocalyptic number.

2014102023 is a deficient number, since it is larger than the sum of its proper divisors (757995513).

2014102023 is a wasteful number, since it uses less digits than its factorization.

2014102023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21657045.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 2014102023 is about 44878.7480106119. The cubic root of 2014102023 is about 1262.8753563909.

Adding to 2014102023 its reverse (3202014102), we get a palindrome (5216116125).

The spelling of 2014102023 in words is "two billion, fourteen million, one hundred two thousand, twenty-three".

Divisors: 1 3 31 93 21657011 64971033 671367341 2014102023