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2014102100211 = 32923150598853
BaseRepresentation
bin11101010011110001110…
…101110001100011110011
321010112202020102202200220
4131103301311301203303
5230444340114201321
64141133221544123
7265341220243605
oct35236165614363
97115666382626
102014102100211
117071a3145463
1228641a875043
13117c10070976
146d6a9743175
15375d107c9c6
hex1d4f1d718f3

2014102100211 has 8 divisors (see below), whose sum is σ = 2778071862480. Its totient is φ = 1296433535712.

The previous prime is 2014102100203. The next prime is 2014102100233. The reversal of 2014102100211 is 1120012014102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2014102100211 - 23 = 2014102100203 is a prime.

It is a super-2 number, since 2×20141021002112 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2014102100291) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11575299340 + ... + 11575299513.

It is an arithmetic number, because the mean of its divisors is an integer number (347258982810).

Almost surely, 22014102100211 is an apocalyptic number.

2014102100211 is a deficient number, since it is larger than the sum of its proper divisors (763969762269).

2014102100211 is a wasteful number, since it uses less digits than its factorization.

2014102100211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23150598885.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 2014102100211 its reverse (1120012014102), we get a palindrome (3134114114313).

The spelling of 2014102100211 in words is "two trillion, fourteen billion, one hundred two million, one hundred thousand, two hundred eleven".

Divisors: 1 3 29 87 23150598853 69451796559 671367366737 2014102100211