Base | Representation |
---|---|
bin | 11101010011110001110… |
… | …101110001100011101011 |
3 | 21010112202020102202200121 |
4 | 131103301311301203223 |
5 | 230444340114201303 |
6 | 4141133221544111 |
7 | 265341220243564 |
oct | 35236165614353 |
9 | 7115666382617 |
10 | 2014102100203 |
11 | 7071a3145456 |
12 | 28641a875037 |
13 | 117c1007096b |
14 | 6d6a974316b |
15 | 375d107c9bd |
hex | 1d4f1d718eb |
2014102100203 has 2 divisors, whose sum is σ = 2014102100204. Its totient is φ = 2014102100202.
The previous prime is 2014102100177. The next prime is 2014102100233. The reversal of 2014102100203 is 3020012014102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2014102100203 is a prime.
It is not a weakly prime, because it can be changed into another prime (2014102100233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007051050101 + 1007051050102.
It is an arithmetic number, because the mean of its divisors is an integer number (1007051050102).
Almost surely, 22014102100203 is an apocalyptic number.
2014102100203 is a deficient number, since it is larger than the sum of its proper divisors (1).
2014102100203 is an equidigital number, since it uses as much as digits as its factorization.
2014102100203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 2014102100203 its reverse (3020012014102), we get a palindrome (5034114114305).
The spelling of 2014102100203 in words is "two trillion, fourteen billion, one hundred two million, one hundred thousand, two hundred three".
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