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20141314143 = 367100205543
BaseRepresentation
bin10010110000100001…
…000001000001011111
31220222200102202210220
4102300201001001133
5312222134023033
613130334132423
71312056226326
oct226041010137
956880382726
1020141314143
1185a6279475
123aa1351113
131b8ca55182
14d90d8d0bd
157cd381bb3
hex4b084105f

20141314143 has 8 divisors (see below), whose sum is σ = 27255907968. Its totient is φ = 13227131544.

The previous prime is 20141314103. The next prime is 20141314177. The reversal of 20141314143 is 34141314102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20141314143 - 228 = 19872878687 is a prime.

It is a super-3 number, since 3×201413141433 (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20141314103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50102571 + ... + 50102972.

It is an arithmetic number, because the mean of its divisors is an integer number (3406988496).

Almost surely, 220141314143 is an apocalyptic number.

20141314143 is a deficient number, since it is larger than the sum of its proper divisors (7114593825).

20141314143 is a wasteful number, since it uses less digits than its factorization.

20141314143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100205613.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 20141314143 its reverse (34141314102), we get a palindrome (54282628245).

The spelling of 20141314143 in words is "twenty billion, one hundred forty-one million, three hundred fourteen thousand, one hundred forty-three".

Divisors: 1 3 67 201 100205543 300616629 6713771381 20141314143