Base | Representation |
---|---|
bin | 11101010011110011101… |
… | …100110011101111110011 |
3 | 21010112211102011002200011 |
4 | 131103303230303233303 |
5 | 230444421111214212 |
6 | 4141140254435351 |
7 | 265342046415625 |
oct | 35236354635763 |
9 | 7115742132604 |
10 | 2014133304307 |
11 | 707209818573 |
12 | 286429202b57 |
13 | 117c16677a27 |
14 | 6d6ad946c15 |
15 | 375d3b934a7 |
hex | 1d4f3b33bf3 |
2014133304307 has 2 divisors, whose sum is σ = 2014133304308. Its totient is φ = 2014133304306.
The previous prime is 2014133304259. The next prime is 2014133304331. The reversal of 2014133304307 is 7034033314102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2014133304307 - 215 = 2014133271539 is a prime.
It is not a weakly prime, because it can be changed into another prime (2014133304347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007066652153 + 1007066652154.
It is an arithmetic number, because the mean of its divisors is an integer number (1007066652154).
Almost surely, 22014133304307 is an apocalyptic number.
2014133304307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2014133304307 is an equidigital number, since it uses as much as digits as its factorization.
2014133304307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 31.
Adding to 2014133304307 its reverse (7034033314102), we get a palindrome (9048166618409).
The spelling of 2014133304307 in words is "two trillion, fourteen billion, one hundred thirty-three million, three hundred four thousand, three hundred seven".
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