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201420124393 is a prime number
BaseRepresentation
bin1011101110010110010…
…0110011000011101001
3201020220022111110221011
42323211210303003221
511300002022440033
6232310420143521
720360243544235
oct2734544630351
9636808443834
10201420124393
1178470455724
1233053237ba1
1315cbc5c5877
149a6a9515c5
15538ce91ccd
hex2ee59330e9

201420124393 has 2 divisors, whose sum is σ = 201420124394. Its totient is φ = 201420124392.

The previous prime is 201420124379. The next prime is 201420124517. The reversal of 201420124393 is 393421024102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 178885010704 + 22535113689 = 422948^2 + 150117^2 .

It is a cyclic number.

It is not a de Polignac number, because 201420124393 - 25 = 201420124361 is a prime.

It is not a weakly prime, because it can be changed into another prime (201420124193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100710062196 + 100710062197.

It is an arithmetic number, because the mean of its divisors is an integer number (100710062197).

Almost surely, 2201420124393 is an apocalyptic number.

It is an amenable number.

201420124393 is a deficient number, since it is larger than the sum of its proper divisors (1).

201420124393 is an equidigital number, since it uses as much as digits as its factorization.

201420124393 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 201420124393 its reverse (393421024102), we get a palindrome (594841148495).

The spelling of 201420124393 in words is "two hundred one billion, four hundred twenty million, one hundred twenty-four thousand, three hundred ninety-three".