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201420124601 is a prime number
BaseRepresentation
bin1011101110010110010…
…0110011000110111001
3201020220022111111012212
42323211210303012321
511300002022441401
6232310420144505
720360243544653
oct2734544630671
9636808444185
10201420124601
11784704558a3
1233053238135
1315cbc5c59a7
149a6a9516d3
15538ce91dbb
hex2ee59331b9

201420124601 has 2 divisors, whose sum is σ = 201420124602. Its totient is φ = 201420124600.

The previous prime is 201420124589. The next prime is 201420124643. The reversal of 201420124601 is 106421024102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 180727014400 + 20693110201 = 425120^2 + 143851^2 .

It is a cyclic number.

It is not a de Polignac number, because 201420124601 - 210 = 201420123577 is a prime.

It is a super-3 number, since 3×2014201246013 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (201420124651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100710062300 + 100710062301.

It is an arithmetic number, because the mean of its divisors is an integer number (100710062301).

Almost surely, 2201420124601 is an apocalyptic number.

It is an amenable number.

201420124601 is a deficient number, since it is larger than the sum of its proper divisors (1).

201420124601 is an equidigital number, since it uses as much as digits as its factorization.

201420124601 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 201420124601 its reverse (106421024102), we get a palindrome (307841148703).

The spelling of 201420124601 in words is "two hundred one billion, four hundred twenty million, one hundred twenty-four thousand, six hundred one".