Base | Representation |
---|---|
bin | 11101010011111010110… |
… | …110001011010010101011 |
3 | 21010120010202202110101221 |
4 | 131103322312023102223 |
5 | 231000142304404210 |
6 | 4141200220322511 |
7 | 265345033465441 |
oct | 35237266132253 |
9 | 7116122673357 |
10 | 2014253200555 |
11 | 707270469382 |
12 | 2864613a3437 |
13 | 117c3546665b |
14 | 6d6c1836b91 |
15 | 375de4781da |
hex | 1d4fad8b4ab |
2014253200555 has 24 divisors (see below), whose sum is σ = 2551336257744. Its totient is φ = 1526399899200.
The previous prime is 2014253200543. The next prime is 2014253200573. The reversal of 2014253200555 is 5550023524102.
It is not a de Polignac number, because 2014253200555 - 229 = 2013716329643 is a prime.
It is a super-2 number, since 2×20142532005552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2014253200555.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 15206160 + ... + 15338050.
It is an arithmetic number, because the mean of its divisors is an integer number (106305677406).
Almost surely, 22014253200555 is an apocalyptic number.
2014253200555 is a deficient number, since it is larger than the sum of its proper divisors (537083057189).
2014253200555 is a wasteful number, since it uses less digits than its factorization.
2014253200555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140395 (or 140376 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 34.
Adding to 2014253200555 its reverse (5550023524102), we get a palindrome (7564276724657).
The spelling of 2014253200555 in words is "two trillion, fourteen billion, two hundred fifty-three million, two hundred thousand, five hundred fifty-five".
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