Base | Representation |
---|---|
bin | 1001001010001111100001… |
… | …10110101010101110000011 |
3 | 2122022122222020100121120021 |
4 | 10211013300312222232003 |
5 | 10120011123440413124 |
6 | 110501344254554311 |
7 | 4146202564223143 |
oct | 445076066525603 |
9 | 78278866317507 |
10 | 20143142513539 |
11 | 6466727900101 |
12 | 2313a61808997 |
13 | b3164ac376a6 |
14 | 4d8d0cd8c923 |
15 | 24de818ec7e4 |
hex | 1251f0daab83 |
20143142513539 has 2 divisors, whose sum is σ = 20143142513540. Its totient is φ = 20143142513538.
The previous prime is 20143142513521. The next prime is 20143142513567. The reversal of 20143142513539 is 93531524134102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20143142513539 - 211 = 20143142511491 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20143142513495 and 20143142513504.
It is not a weakly prime, because it can be changed into another prime (20143142517539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10071571256769 + 10071571256770.
It is an arithmetic number, because the mean of its divisors is an integer number (10071571256770).
Almost surely, 220143142513539 is an apocalyptic number.
20143142513539 is a deficient number, since it is larger than the sum of its proper divisors (1).
20143142513539 is an equidigital number, since it uses as much as digits as its factorization.
20143142513539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 43.
The spelling of 20143142513539 in words is "twenty trillion, one hundred forty-three billion, one hundred forty-two million, five hundred thirteen thousand, five hundred thirty-nine".
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