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2014411330073 is a prime number
BaseRepresentation
bin11101010100000100010…
…001011001001000011001
321010120112210022021022202
4131110010101121020121
5231001003300030243
64141224025455545
7265351663534442
oct35240421311031
97116483267282
102014411330073
1170734175342a
122864a63415b5
13117c5c15090c
146d6d883a2c9
15375ed2b14b8
hex1d504459219

2014411330073 has 2 divisors, whose sum is σ = 2014411330074. Its totient is φ = 2014411330072.

The previous prime is 2014411330033. The next prime is 2014411330081. The reversal of 2014411330073 is 3700331144102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1551539289664 + 462872040409 = 1245608^2 + 680347^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2014411330073 is a prime.

It is not a weakly prime, because it can be changed into another prime (2014411330003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007205665036 + 1007205665037.

It is an arithmetic number, because the mean of its divisors is an integer number (1007205665037).

Almost surely, 22014411330073 is an apocalyptic number.

It is an amenable number.

2014411330073 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014411330073 is an equidigital number, since it uses as much as digits as its factorization.

2014411330073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 2014411330073 its reverse (3700331144102), we get a palindrome (5714742474175).

The spelling of 2014411330073 in words is "two trillion, fourteen billion, four hundred eleven million, three hundred thirty thousand, seventy-three".