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20144113441 = 31649810111
BaseRepresentation
bin10010110000101011…
…101100011100100001
31220222212200222201121
4102300223230130201
5312223343112231
613130514132241
71312122065464
oct226053543441
956885628647
1020144113441
1185a7910641
123aa2281081
131b904c536a
14d914bb2db
157cd736311
hex4b0aec721

20144113441 has 4 divisors (see below), whose sum is σ = 20793923584. Its totient is φ = 19494303300.

The previous prime is 20144113421. The next prime is 20144113523. The reversal of 20144113441 is 14431144102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14431144102 = 27215572051.

It is a cyclic number.

It is not a de Polignac number, because 20144113441 - 225 = 20110559009 is a prime.

It is a super-3 number, since 3×201441134413 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20144113421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 324905025 + ... + 324905086.

It is an arithmetic number, because the mean of its divisors is an integer number (5198480896).

Almost surely, 220144113441 is an apocalyptic number.

It is an amenable number.

20144113441 is a deficient number, since it is larger than the sum of its proper divisors (649810143).

20144113441 is an equidigital number, since it uses as much as digits as its factorization.

20144113441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 649810142.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 20144113441 its reverse (14431144102), we get a palindrome (34575257543).

The spelling of 20144113441 in words is "twenty billion, one hundred forty-four million, one hundred thirteen thousand, four hundred forty-one".

Divisors: 1 31 649810111 20144113441