Base | Representation |
---|---|
bin | 1001001010010001010110… |
… | …01111001010001001010011 |
3 | 2122022202111111110022012001 |
4 | 10211020223033022021103 |
5 | 10120020130213342433 |
6 | 110502025405014431 |
7 | 4146236056636405 |
oct | 445105317121123 |
9 | 78282444408161 |
10 | 20144122012243 |
11 | 646708a7a0a69 |
12 | 2314095854417 |
13 | b31775b47218 |
14 | 4d8da30c0b75 |
15 | 24dedc8ce57d |
hex | 12522b3ca253 |
20144122012243 has 2 divisors, whose sum is σ = 20144122012244. Its totient is φ = 20144122012242.
The previous prime is 20144122012219. The next prime is 20144122012253. The reversal of 20144122012243 is 34221022144102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20144122012243 - 225 = 20144088457811 is a prime.
It is not a weakly prime, because it can be changed into another prime (20144122012253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072061006121 + 10072061006122.
It is an arithmetic number, because the mean of its divisors is an integer number (10072061006122).
Almost surely, 220144122012243 is an apocalyptic number.
20144122012243 is a deficient number, since it is larger than the sum of its proper divisors (1).
20144122012243 is an equidigital number, since it uses as much as digits as its factorization.
20144122012243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 20144122012243 its reverse (34221022144102), we get a palindrome (54365144156345).
The spelling of 20144122012243 in words is "twenty trillion, one hundred forty-four billion, one hundred twenty-two million, twelve thousand, two hundred forty-three".
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