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20144133133 = 79254989027
BaseRepresentation
bin10010110000101011…
…110001010000001101
31220222212201222201221
4102300223301100031
5312223344230013
613130514403341
71312122210055
oct226053612015
956885658657
1020144133133
1185a7924413
123aa2290551
131b90501307
14d914c4565
157cd73c08d
hex4b0af140d

20144133133 has 4 divisors (see below), whose sum is σ = 20399122240. Its totient is φ = 19889144028.

The previous prime is 20144133109. The next prime is 20144133143. The reversal of 20144133133 is 33133144102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20144133133 - 29 = 20144132621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20144133098 and 20144133107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20144133143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127494435 + ... + 127494592.

It is an arithmetic number, because the mean of its divisors is an integer number (5099780560).

Almost surely, 220144133133 is an apocalyptic number.

It is an amenable number.

20144133133 is a deficient number, since it is larger than the sum of its proper divisors (254989107).

20144133133 is an equidigital number, since it uses as much as digits as its factorization.

20144133133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 254989106.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 20144133133 its reverse (33133144102), we get a palindrome (53277277235).

The spelling of 20144133133 in words is "twenty billion, one hundred forty-four million, one hundred thirty-three thousand, one hundred thirty-three".

Divisors: 1 79 254989027 20144133133