Base | Representation |
---|---|
bin | 1001001010010001111101… |
… | …10110101110001100110011 |
3 | 2122022210100102210021012011 |
4 | 10211020332312232030303 |
5 | 10120021313443310033 |
6 | 110502122203343351 |
7 | 4146250164365521 |
oct | 445107666561463 |
9 | 78283312707164 |
10 | 20144451150643 |
11 | 6467239567576 |
12 | 2314167b21b57 |
13 | b317c90a7a81 |
14 | 4d8dd4abb311 |
15 | 24e00b746ccd |
hex | 12523edae333 |
20144451150643 has 2 divisors, whose sum is σ = 20144451150644. Its totient is φ = 20144451150642.
The previous prime is 20144451150589. The next prime is 20144451150667. The reversal of 20144451150643 is 34605115444102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20144451150643 - 217 = 20144451019571 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20144451150596 and 20144451150605.
It is not a weakly prime, because it can be changed into another prime (20144451150683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072225575321 + 10072225575322.
It is an arithmetic number, because the mean of its divisors is an integer number (10072225575322).
Almost surely, 220144451150643 is an apocalyptic number.
20144451150643 is a deficient number, since it is larger than the sum of its proper divisors (1).
20144451150643 is an equidigital number, since it uses as much as digits as its factorization.
20144451150643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 40.
Adding to 20144451150643 its reverse (34605115444102), we get a palindrome (54749566594745).
The spelling of 20144451150643 in words is "twenty trillion, one hundred forty-four billion, four hundred fifty-one million, one hundred fifty thousand, six hundred forty-three".
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