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20144451150643 is a prime number
BaseRepresentation
bin1001001010010001111101…
…10110101110001100110011
32122022210100102210021012011
410211020332312232030303
510120021313443310033
6110502122203343351
74146250164365521
oct445107666561463
978283312707164
1020144451150643
116467239567576
122314167b21b57
13b317c90a7a81
144d8dd4abb311
1524e00b746ccd
hex12523edae333

20144451150643 has 2 divisors, whose sum is σ = 20144451150644. Its totient is φ = 20144451150642.

The previous prime is 20144451150589. The next prime is 20144451150667. The reversal of 20144451150643 is 34605115444102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20144451150643 - 217 = 20144451019571 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20144451150596 and 20144451150605.

It is not a weakly prime, because it can be changed into another prime (20144451150683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072225575321 + 10072225575322.

It is an arithmetic number, because the mean of its divisors is an integer number (10072225575322).

Almost surely, 220144451150643 is an apocalyptic number.

20144451150643 is a deficient number, since it is larger than the sum of its proper divisors (1).

20144451150643 is an equidigital number, since it uses as much as digits as its factorization.

20144451150643 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 230400, while the sum is 40.

Adding to 20144451150643 its reverse (34605115444102), we get a palindrome (54749566594745).

The spelling of 20144451150643 in words is "twenty trillion, one hundred forty-four billion, four hundred fifty-one million, one hundred fifty thousand, six hundred forty-three".