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20145207614641 is a prime number
BaseRepresentation
bin1001001010010011010111…
…11100011001110010110001
32122022212022011012121201021
410211021223330121302301
510120024341122132031
6110502325225135441
74146305011256104
oct445115374316261
978285264177637
1020145207614641
11646759757212a
12231433932a581
13b318b9a267c5
144d906735273b
1524e052d6e511
hex12526bf19cb1

20145207614641 has 2 divisors, whose sum is σ = 20145207614642. Its totient is φ = 20145207614640.

The previous prime is 20145207614617. The next prime is 20145207614671. The reversal of 20145207614641 is 14641670254102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19289628864016 + 855578750625 = 4391996^2 + 924975^2 .

It is a cyclic number.

It is not a de Polignac number, because 20145207614641 - 231 = 20143060130993 is a prime.

It is not a weakly prime, because it can be changed into another prime (20145207614611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072603807320 + 10072603807321.

It is an arithmetic number, because the mean of its divisors is an integer number (10072603807321).

Almost surely, 220145207614641 is an apocalyptic number.

It is an amenable number.

20145207614641 is a deficient number, since it is larger than the sum of its proper divisors (1).

20145207614641 is an equidigital number, since it uses as much as digits as its factorization.

20145207614641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 322560, while the sum is 43.

Adding to 20145207614641 its reverse (14641670254102), we get a palindrome (34786877868743).

The spelling of 20145207614641 in words is "twenty trillion, one hundred forty-five billion, two hundred seven million, six hundred fourteen thousand, six hundred forty-one".