Base | Representation |
---|---|
bin | 101101110100001110100011… |
… | …011001110000011100110011 |
3 | 222102110022122100120100211101 |
4 | 231310032203121300130303 |
5 | 202402343304311130344 |
6 | 1552320201524425231 |
7 | 60304655620016104 |
oct | 5564164331603463 |
9 | 872408570510741 |
10 | 201501132130099 |
11 | 59228171a6684a |
12 | 1a724329548217 |
13 | 88586240c5849 |
14 | 37a89c77943ab |
15 | 1846790a199d4 |
hex | b743a3670733 |
201501132130099 has 2 divisors, whose sum is σ = 201501132130100. Its totient is φ = 201501132130098.
The previous prime is 201501132130063. The next prime is 201501132130121. The reversal of 201501132130099 is 990031231105102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201501132130099 - 27 = 201501132129971 is a prime.
It is a super-2 number, since 2×2015011321300992 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201501132133099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100750566065049 + 100750566065050.
It is an arithmetic number, because the mean of its divisors is an integer number (100750566065050).
Almost surely, 2201501132130099 is an apocalyptic number.
201501132130099 is a deficient number, since it is larger than the sum of its proper divisors (1).
201501132130099 is an equidigital number, since it uses as much as digits as its factorization.
201501132130099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 37.
The spelling of 201501132130099 in words is "two hundred one trillion, five hundred one billion, one hundred thirty-two million, one hundred thirty thousand, ninety-nine".
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