Base | Representation |
---|---|
bin | 10010110001000011… |
… | …000101010001100011 |
3 | 1221000022020110220001 |
4 | 102301003011101203 |
5 | 312231430310301 |
6 | 13131253400431 |
7 | 1312225152241 |
oct | 226103052143 |
9 | 57008213801 |
10 | 20150244451 |
11 | 8600318997 |
12 | 3aa4339117 |
13 | 1b91860b8c |
14 | d92235791 |
15 | 7ce047c01 |
hex | 4b10c5463 |
20150244451 has 2 divisors, whose sum is σ = 20150244452. Its totient is φ = 20150244450.
The previous prime is 20150244427. The next prime is 20150244469. The reversal of 20150244451 is 15444205102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20150244451 - 211 = 20150242403 is a prime.
It is not a weakly prime, because it can be changed into another prime (20150244151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10075122225 + 10075122226.
It is an arithmetic number, because the mean of its divisors is an integer number (10075122226).
Almost surely, 220150244451 is an apocalyptic number.
20150244451 is a deficient number, since it is larger than the sum of its proper divisors (1).
20150244451 is an equidigital number, since it uses as much as digits as its factorization.
20150244451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6400, while the sum is 28.
Adding to 20150244451 its reverse (15444205102), we get a palindrome (35594449553).
The spelling of 20150244451 in words is "twenty billion, one hundred fifty million, two hundred forty-four thousand, four hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.232 sec. • engine limits •