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201504552131 is a prime number
BaseRepresentation
bin1011101110101010011…
…0110111010011000011
3201021010012100212000102
42323222212313103003
511300140131132011
6232323033513015
720362320301241
oct2735246672303
9637105325012
10201504552131
1178504080513
123307757276b
1316003c463cc
149a77c4b791
1553955bc73b
hex2eea9b74c3

201504552131 has 2 divisors, whose sum is σ = 201504552132. Its totient is φ = 201504552130.

The previous prime is 201504552127. The next prime is 201504552169. The reversal of 201504552131 is 131255405102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201504552131 - 22 = 201504552127 is a prime.

It is a super-2 number, since 2×2015045521312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201504552094 and 201504552103.

It is not a weakly prime, because it can be changed into another prime (201504552121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100752276065 + 100752276066.

It is an arithmetic number, because the mean of its divisors is an integer number (100752276066).

Almost surely, 2201504552131 is an apocalyptic number.

201504552131 is a deficient number, since it is larger than the sum of its proper divisors (1).

201504552131 is an equidigital number, since it uses as much as digits as its factorization.

201504552131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6000, while the sum is 29.

Adding to 201504552131 its reverse (131255405102), we get a palindrome (332759957233).

The spelling of 201504552131 in words is "two hundred one billion, five hundred four million, five hundred fifty-two thousand, one hundred thirty-one".