Base | Representation |
---|---|
bin | 11101010100101110100… |
… | …000111010100001000111 |
3 | 21010122101011212120101200 |
4 | 131110232200322201013 |
5 | 231003431212321210 |
6 | 4141422223553543 |
7 | 265405360512231 |
oct | 35245640724107 |
9 | 7118334776350 |
10 | 2015120042055 |
11 | 70767580320a |
12 | 28666375b8b3 |
13 | 118042c20513 |
14 | 6d764a01251 |
15 | 376406050c0 |
hex | 1d52e83a847 |
2015120042055 has 24 divisors (see below), whose sum is σ = 3493072477440. Its totient is φ = 1074669846720.
The previous prime is 2015120042053. The next prime is 2015120042069. The reversal of 2015120042055 is 5502400215102.
2015120042055 is a `hidden beast` number, since 20 + 15 + 1 + 200 + 420 + 5 + 5 = 666.
It is not a de Polignac number, because 2015120042055 - 21 = 2015120042053 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2015120042053) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 458151 + ... + 2059160.
It is an arithmetic number, because the mean of its divisors is an integer number (145544686560).
Almost surely, 22015120042055 is an apocalyptic number.
2015120042055 is a deficient number, since it is larger than the sum of its proper divisors (1477952435385).
2015120042055 is a wasteful number, since it uses less digits than its factorization.
2015120042055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2535111 (or 2535108 counting only the distinct ones).
The product of its (nonzero) digits is 4000, while the sum is 27.
Adding to 2015120042055 its reverse (5502400215102), we get a palindrome (7517520257157).
The spelling of 2015120042055 in words is "two trillion, fifteen billion, one hundred twenty million, forty-two thousand, fifty-five".
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