Base | Representation |
---|---|
bin | 101101110100011011111100… |
… | …100101010011111011111001 |
3 | 222102111200202121011002111112 |
4 | 231310123330211103323321 |
5 | 202403112232341430040 |
6 | 1552330540533410105 |
7 | 60306005163253166 |
oct | 5564337445237371 |
9 | 872450677132445 |
10 | 201515513233145 |
11 | 592332817a3381 |
12 | 1a727081799935 |
13 | 8859aa665a987 |
14 | 37a958d71306d |
15 | 1846d3332c365 |
hex | b746fc953ef9 |
201515513233145 has 64 divisors (see below), whose sum is σ = 258055856239104. Its totient is φ = 150727812618240.
The previous prime is 201515513233123. The next prime is 201515513233157. The reversal of 201515513233145 is 541332315515102.
It is not a de Polignac number, because 201515513233145 - 212 = 201515513229049 is a prime.
It is a super-2 number, since 2×2015155132331452 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4028593235 + ... + 4028643255.
It is an arithmetic number, because the mean of its divisors is an integer number (4032122753736).
Almost surely, 2201515513233145 is an apocalyptic number.
It is an amenable number.
201515513233145 is a deficient number, since it is larger than the sum of its proper divisors (56540343005959).
201515513233145 is a wasteful number, since it uses less digits than its factorization.
201515513233145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52562.
The product of its (nonzero) digits is 270000, while the sum is 41.
Adding to 201515513233145 its reverse (541332315515102), we get a palindrome (742847828748247).
The spelling of 201515513233145 in words is "two hundred one trillion, five hundred fifteen billion, five hundred thirteen million, two hundred thirty-three thousand, one hundred forty-five".
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